trackfodder
Member
HEY NEAT TIMES ! I think figuring the drive ratio is simpler than you think. The tire diameter on a 26" wheel is roughly 2" less at the sidewall. Assume 24" and a clutch diameter of 4" and it is simple division. The ratio engine to wheel is 6:1, which is a pretty good starting place from my experience with 15 or so homebuilt motorbikes. Take the engine RPM divided by the drive ratio and that is the rpm of the rear wheel. Take the circumference of the tire in inches into inches in a mile (63360)and get rev/min. Multiply by 60 and get RPH. For instance, motor rpm 3000 divided by 6=500 RPM at rear wheel. assume tire circumference as 81.68 X 500=40840.7 in/min.divided by 12=3403.39 ft/minX 60= ft/hr=204203.4 ft/hr divided by 5280 =38.67 mph. That's reasonable. I probably took the long way around, but I had to think it through. KW